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Chapter 7 Part 3 (Goodness of Fit Test) Find the following chi-square distribution values from the Table in your appendix (Table B.5). 1. Zags = with d.f. = 5 a. 27.49 b. 23.21 c. 11.07 d. 28.41 2. Xo.97s= with d.f. = 15 a. 27.49 b. 23.21 c. 11.07 d. 28.41 3. Xago = with d.f. = 20 a. 27.49 b. 23.21 c. 11.07 d. 28.41 4. X39 = with d.f. = 10 a. 27.49 b. 23.21 c. 11.07 d. 28.41 Use the information below to answer questions 5-8. As the first step in a study to evaluate highway fatalities, the traffic department wants to evaluate whether the left-hand lane of a three-lane highway services twice the traffic volume as the other two lanes. The following data were collected, reflecting the numbers of vehicles traveling each of the three lanes during the rush hour. Use the data to test the claim that twice as many vehicles travel the left lane as compared to the other two lanes ( a = 0.05 ). Right Lane Center Lane Left Lane Total Number of 205 220 575 1000 Vehicles 1. State the null and alternative hypothesis. a. Ho: Pright = 0.25, Pcenter = 0.25, Pleft = 0.50 HI: Ho is false b. Ho: Pright = 0.50, Pcenter = 0.50, pleft = 0.50 HI: Ho is false C. Ho: Pright = 0.25, Pcenter = 0.25, pleft = 0.25 HI: Ho is false d. Ho: Pright = 0 , Pcenter = 0, Pleft = 2 HI: Ho is false 2. What is the critical value of the test and your decision rule? a. 1.96; Reject Ho if the test statistic is greater than or equal to 1.96, otherwise not enough evidence to reject Ho. b. 5.99; Reject Ho if the test statistic is greater than or equal to 5.99, otherwise not enough evidence to reject Ho. C. 1.645; Reject Ho if the test statistic is greater than or equal to 1.645, otherwise not enough evidence to reject Ho. d. 7.38; Reject Ho if the test statistic is greater than or equal to 7.38, otherwise not enough evidence to reject Ho. 3. What is the test statistic? a. 1.96 b. 5.99 C. 1.645 d. 22.95 4. State your conclusion. a. Reject Ho b. Not enough evidence to reject Ho