Determine the definite integral value of a function with negative output values.

Evaluate 3 (1x/- 7) dx using the following graph. -6 -5 -4 -3 -2 -1 2 3 4 5 -1 -2 -4 -5 Xa.) O (1x| - 7)dx = - 36.5 3 b.) .4 O (1x| -7)dx =36.5 - 3 c.) 4 O (|x| - 7)dx =3.5 3 d.) O (1x/- 7)dx = - 3.5 3