Determine the direction of the induced current in the loop, the magnitude of the induced emf, the magnitude of the current in the lightbulb, and the power output of the lightbulb: AD B At Area increases as the rod moves right. 10- bulb 3 = 90 A (BA cos 0)| At L= 1.2 m (6.0 m/s) |B(AA) 3 Only area changes!: || | = At 0 X Bex (0.20 T) AA_A(Lx) Ax =L=Lv At At At Q: What is the direction of current in it? ||= BLv