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Determine the energy (in Me) released in the fission reaction In + 235U-> 48Zr + 135Te + 3(3n) The atomic masses are 235U, 235.0439 u;

Determine the energy (in Me) released in the fission reaction

In + 235U-> 48Zr + 135Te + 3(3n)

The atomic masses are 235U, 235.0439 u; 28Zr, 97.9127 u; and 13Te, 134.9165 u.

Express the values to 3 significant figures, if necessary.

image text in transcribed
B1. Determine the energy (in MeV) released in the fission reaction on + 2351 920- 987. 40Zr + 135T 52Te + 3(in) The atomic masses are 920, 235.0439 u; 28Zr, 97.9127 u; and 135Te, 134.9165 u. (6 marks) Express the values to 3 significant figures, if necessary

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