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Determine the limiting reactant. Justify. Propylene (C3H6) reacts with oxygen and hydrogen to produce Propylene oxide (C3H8O). A side reaction resulted in reacting propylene with
Determine the limiting reactant. Justify.
Propylene (C3H6) reacts with oxygen and hydrogen to produce Propylene oxide (C3H8O). A side reaction resulted in reacting propylene with hydrogen and produces propane (C3H8). The two reactions are taking place as follows: C3H6+H2+1/2O2C3H8OC3H6+H2C3H8Rxn1Rxn2 A mixture of 35molAir/h,4mol propylene /h, and 12.6molH2/h along with 5000molCO/h are fed to a continuous reactor. Carbon dioxide is used as inert solvent. The single-pass conversion of limiting reactant is 0.15 . The fractional yield of C3H6 to C3H8O (i.e., fraction of moles of C3H6 reacted to produce C3H8O ) is 0.8Step by Step Solution
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