Determine the mean and median of the following data. 5 7 11 13 -1 12 -9 5 -2 Determine the mean and median accurate to 1 decimal place. 1. Mean = 2. Median = Determine the mode. If there is no mode, enter DIVE. If there are multiple modes, enter them separated by commas. For example, if the modes are 6 and 5, enter 6, 5. 3. Mode =Dylan's gas purchases last month were as follows: Price per litre $1.29 $1.70 $1.42 $1.68 $1.53 Number of litres 53.6 56.5 45.6 59.5 25.2 Calculate the total purchase price and the weighted mean price per litre. Round answers correct to the nearest cent. a. Total purchase price = $ b. Weighted mean = $ per litreDetermine the shape of the distribution pictured below and the measure of center that should be used. 30 25 Frequency 0.5 15 2.5 3.5 4.5 5.5 6.5 7.5 data Q O Uniform O Bell-shaped O Skewed-right O Skewed-left Based on the shape of the histogram above, what measure of center should be used? O mean O medianThe mean of the 5 observations in the following table is 3. 1. Fill in the missing values. Download CSV 2. Determine the following sums: DC] zenQC] 9 -5 2 Download CSV 2. Determine the following sums: [(x - 3) = [(x - 2)? = 3. Sample variance, 8 = 4. Report the sample standard deviation accurate to 2 decimal places. Sample standard deviation, s =. Question 5 0/2 pts 5 3 0 Details Using your calculator or software, find the range, standard deviation, and variance. The table below gives the number of hours spent watching TV last week by a sample of 29 children. 31 35 21 13 9 35 15 10 29 14 12 21 34 38 38 25 18 9 8 9 20 37 34 14 29 14 22 27 34 Download CSV Round answers to two decimals places. Range = Sample Variance = Sample Standard Deviation =The mean of the 5 observations in the following table is '15. 1. Find the missing values. "m 2. Report the sample standard deviation accurate to at least 2 decimal places. The sample standard deviation, 3 = C] - The Acme Companyr manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 35 ounces and a standard deviation of 3 ounces. E DIS pts E} 3 G) Details Use the Standard Deviation Rule, also known as the Empirioal Rule. Suggestion: sketch the distribution in order to answer these questions. a) 95% of the widget weights lie between and b} What percentage of the widget weights lie between 32 and 41 ounces? o} What percentage of the widget weights lie below 44 ? Era . Question 8 0/3 pts ) 3 0 Details Consider the following bell-shaped distribution where 42 and 70 are two standard deviations from the mean each. 35 42 56 63 70 77 Q Determine the Mean and Variance of the distribution. 1. Mean = 2. Variance = Use the empirical rule or your knowledge of the normal disdtribution to answer the following. Report answers as integers. 3. The lower limit for the highest 2.5% of the data is approximately =35 42 49 56 63 70 77 a Determine the Mean and Variance of the distribution. 1. Mean = 2. Variance = Use the empirical rule or your knowledge of the normal disdtribution to answer the following. Report answers as integers. 3. The lower limit for the highest 2.5% of the data is approximately = 4. The upper limit for the lowest 16% of the data is approximately = 5. The range of the middle 68% of the data is approximately =The time needed to complete a math examination is bell-shaped with a mean of 120 minutes and a standard deviation of 5 minutes. a) What percentage of students will complete the exam in 110 minutes or less? b} Assume that the class has 150 students and that the examination period is 1313 minutes in length. How manyr students do you expect will not be able to complete the exam in the allotted time? Round answer to the nearest whole number. |:| c} A student is classified as extremer "efficient" if the amount of time spent on the exam is the lowest 2.5% for the distribution. What is the upper limit for the time it takes an extremely "efficient" student to finish the exam? Given the following table of unsorted values, calculate the indicated locator and percentile. Do not round your results. 51 16 18 21 55 31 79 100 73 20 5 47 93 38 17 7 88 32 65 30 45 8 19 60 43 34 59 29 19 69 42 15 44 90 39 27 68 95 26 98 12 63 40 92 57 11 86 46 53 37 77 99 58 13 85 25 14 74 83 33 89 76 56 36 66 6 78 50 41 10 71 94 35 70 72 67 96 28 97 64 a) Determine the locator for the 70th percentile, L70. L70 = b) Find the 70th percentile, Pro- P70= c) Approximately, what percent of the scores in a dataset are below the 70th percentile?. Question 11 0/5 pts 1 3 0 Details The 5-number summary for a data set is as follows: - 58 - 9 16 25 73 a. The range of the dataset = b. The third (upper) quartile = c. The interquartile range, IQR = and it represents the range of the middle % of the data. d. The 50th percentile = e. About 75% of the data are greater than f. There are about of the data between - 58 and 73