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Determine the sentence stored in the linked list Given the following structure: struct 1node char *str; // points to 16 character string struct lnode *next;
Determine the sentence stored in the linked list
Given the following structure: struct 1node char *str; // points to 16 character string struct lnode *next; And we know that the variable list is the start of the list, so we execute the following command in gdb to find the start of the list (gdb) print list $2 = (struct inode *) 0x601150 (gdb) x/52gx 0x601000 0x601000 0x601010: 0x601020 0x601030 0x601040: 0x60105e 0x601060: 0x601070: 0x601080 0x601090: 0x6010a0: 0x6010b0: 0x6010ce: 0x6010d0: 0x6010e0: 0x6010fe 0601 100 : 0x601110: 0x601120: 0x601130: 0x601140: 0x601150: 0x601160: 0x601170: 0x601180 0x601190 0x0000000000000000 0x0000000000601170 0x0000000000000000 0x0000000000601070 0x0000000000000000 0x207469202c65636e 0x0000000000000000 0x6b20666f20796d65 0x0000000000000000 0x0000000000601050 0x0000000000000000 0x002e656764656c77 0x0000000000000000 0x746f6e2073692065 0x0000000000000000 0 00000000006810 0 0 0000000000000000 0x6165726720656854 0x00000000006010f0 0x0000000000000021 0x0000000000601130 0x0000000000000021 0@020656874207369 0x0000000000000021 0x006764656c776f6e 0x0000000000000021 0x0000000000601010 0x0000000000000021 0x0000000000000021 0x0061726f6e676920 0x0000000000000021 0x00000000006010d0 0x0000000000000000 0x0000000000601110 0x0000000000000000 0x6e6f6973756c6c69 0x0000000000000021 0x006e652074736574 0x0000000000000021 0x0000000000601090 0x0000000000000021 0x0000000000601030 0x0000000000000021 0x006f6e6b20666f20 0x0000000000020e81 0x0000000000000000 Starting Address: Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) 1.2) Determine the sentence being stored in the linked list. (15 points) Given the following structure: struct 1node char *str; // points to 16 character string struct lnode *next; And we know that the variable list is the start of the list, so we execute the following command in gdb to find the start of the list (gdb) print list $2 = (struct inode *) 0x601150 (gdb) x/52gx 0x601000 0x601000 0x601010: 0x601020 0x601030 0x601040: 0x60105e 0x601060: 0x601070: 0x601080 0x601090: 0x6010a0: 0x6010b0: 0x6010ce: 0x6010d0: 0x6010e0: 0x6010fe 0601 100 : 0x601110: 0x601120: 0x601130: 0x601140: 0x601150: 0x601160: 0x601170: 0x601180 0x601190 0x0000000000000000 0x0000000000601170 0x0000000000000000 0x0000000000601070 0x0000000000000000 0x207469202c65636e 0x0000000000000000 0x6b20666f20796d65 0x0000000000000000 0x0000000000601050 0x0000000000000000 0x002e656764656c77 0x0000000000000000 0x746f6e2073692065 0x0000000000000000 0 00000000006810 0 0 0000000000000000 0x6165726720656854 0x00000000006010f0 0x0000000000000021 0x0000000000601130 0x0000000000000021 0@020656874207369 0x0000000000000021 0x006764656c776f6e 0x0000000000000021 0x0000000000601010 0x0000000000000021 0x0000000000000021 0x0061726f6e676920 0x0000000000000021 0x00000000006010d0 0x0000000000000000 0x0000000000601110 0x0000000000000000 0x6e6f6973756c6c69 0x0000000000000021 0x006e652074736574 0x0000000000000021 0x0000000000601090 0x0000000000000021 0x0000000000601030 0x0000000000000021 0x006f6e6b20666f20 0x0000000000020e81 0x0000000000000000 Starting Address: Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) Value (in hex) Next Address (in hex) 1.2) Determine the sentence being stored in the linked list. (15 points)Step by Step Solution
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