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determine which alternative should be selected if the analysis period is 18 years, the repeatability assumption does not apply, and a battery system can be

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determine which alternative should be selected if the analysis period is 18 years, the repeatability assumption does not apply, and a battery system can be leased for 8,000$ per year after the useful life of either battery is over. image text in transcribed
e chosen) The MARS the owing tot cash rows of two mutually exclusive alle Capital investment Annual expenses Useful life Market value at end of useful in Lead Acid $6.000 $2.500 12 years Lithium Ion $14.000 $2.400 18 years $2.800 Chap Click the icon to view the Interest and annuity table for discrete compounding when / -5% per year a. Determine which alternative should be selected the repeatability assumption applies 92.1 The AW of the Lead Acid is 5 - 3176 8. (Round to the nearest dollar) Unli The AW of the Lithium ion is 5-3497 6. (Round to the nearest dollar) que Which alternative should be selected? Choose the correct answer below (1/1) (0.88/1 1/1) 1/1) Lead Acid Lithium Ion b. Determine which alternative should be selected if the analysis period is 18 years, the repeatability assumption does not apply, and a battery system can be leased for 5 000 per year after the useful life of the battery is over pre Info TUL TUTUR Given UT- TUTT AE TURBOCOWN - Given P FIP 1.0500 1.1025 1.1576 1.2155 1.2763 1.3401 1.4071 1.4775 1.5513 1.6289 1.7103 1.7959 1.8856 1.9799 2.0789 2.1829 2.2920 2.4066 2.5270 2.6533 Given F PE 0.9524 0.9070 0.8638 0.8227 0.7835 0.7462 0.7107 0.6768 0.6446 0.6139 0.5847 0.5568 0.5303 0.5051 0.4810 0.4581 0.4363 0.4155 0.3957 0.3769 Given A FA 1.0000 2.0500 3.1525 4.3101 5.5256 6.8019 8.1420 9.5491 11.0266 12.5779 14.2068 15.9171 17.7130 19.5986 21.5786 23.6575 25.8404 28.1324 30.5390 33.0660 TOTT Given A PYA 0.9524 1.8594 2.7232 3.5460 4.3295 5.0757 5.7864 6.4632 7.1078 7.7217 8.3064 8.8633 9.3936 9.8986 10.3797 10.8378 11.2741 11.6896 12.0853 12.4622 1.0000 0.4878 0.3172 0.2320 0.1810 0.1470 0.1228 0.1047 0.0907 0.0795 0.0704 0.0628 0.0565 0.0510 0.0463 0.0423 0.0387 0.0355 0.0327 0.0302 TUTTE Given P A/P 1.0500 0.5378 0.3672 0.2820 0.2310 0.1970 0.1728 0.1547 0.1407 0.1295 0.1204 0.1128 0.1065 0.1010 0.0963 0.0923 0.0887 0.0855 0.0827 0.0802 atives (one must be chosen). The MARR is 5% per year. Capital investment Annual expenses Useful life Market value at end of useful life Lead Acid $6,000 $2,500 12 years Lithium Ion $14,000 $2,400 18 years $2,800 $0 mpounding when i = 5% per year

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