Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Did the results match the expectations from a common-sense point of view? Moment of Inertia Collected Data Diameter of Hub 0.0477m Radius of Hub 0.02385m
Did the results match the expectations from a common-sense point of view?
Moment of Inertia | ||
Collected Data | ||
Diameter of Hub | 0.0477m | |
Radius of Hub | 0.02385m | |
Inner Diameter Ring | 0.22m | |
Inner Radius Ring | 0.11m | |
Outer Diameter Ring | 0.0253m | |
Outer Radius Ring | 0.01265m | |
Mass of Ring | 4.844kg | |
Diameter of Disk | 0.253m | |
Radius of Disk | 0.01265m | |
Mass of Disk | 4.963kg | |
Dropped mass for Platform | .1kg | |
Dropped mass for Ring + Platform | .5kg | |
Dropped mass for Disk + Platform | .5kg | |
Acceleration for Platform alone | .2536m/s^2 | |
Acceleration for Platform plus Ring | .03613 rad/s^2 | |
Acceleration for Platform plus Disk | .06211 rad/s^2 | |
Calculations - Platform Alone | ||
T = m(g-a) | 0.955 N | |
Torque = T x RH | 0.022 kg m^2 | |
= a/RH | 10.6 rad/s^2 | |
I of Platform = Torque/ | 0.0021 kg m^2 | |
Calculations - Platform plus Ring | ||
T = m(g-a) | 4.886 N | |
Torque = T x RH | 0.11 Nm | |
= a/RH | 1.51 rad/s^2 | |
I of Platform plus Ring = Torque/ | 0.0769 kg m^2 | |
I of Ring Alone = I(Platform + Ring) - I(Platform Alone) | 0.0747 kg m^2 | |
Calculations - Platform plus Disk | ||
T = m(g-a) | 4.87 N | |
Torque = T x RH | 0.116 Nm | |
= a/RH | 2.604 rad/s^2 | |
I of Platform plus Disk = Torque/ | 0.0446 kg m^2 | |
I of Disk Alone = I(Platform + Disk) - I(Platform Alone) | 0.0422 kg m^2 |
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started