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didnt understand these values corresponding 5 and 6 can you calculate again by writing thanks according to my previous question teacher (c) At 750C(1023K) for
didnt understand these values corresponding 5 and 6 can you calculate again by writing thanks according to my previous question teacher 
(c) At 750C(1023K) for the reaction: 2Zn(l)+O2(g)=2ZnO(s),K3=P021 G3ologpO2=118256cals=RTlnpO2=25.3675 Similarly for the reaction (4): ZnS(s)+23O2(g)=ZnO(s)+SO2(g), we can express: logpO2=12.6507+32logpSO2 On substituting the value of logpO2=25.3675, from Eq. 5 in Eq. 6, we get: logpSO2pSO2=19.0773,=8.371020atmAns Step by Step Solution
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Introduction To Chemical Engineering Thermodynamics
Authors: J.M. Smith, Hendrick Van Ness, Michael Abbott, Mark Swihart
8th Edition
1259696529, 978-1259696527
