Differentiate = X Solution 1 Since both the base and the exponent are variable, we use logarithmic differentiation. In(y) = In(xx) = 9x In(x) y' = 9 + (In(x)) 9 In(x) y' = y + = XX Solution 2 Another method is to write x 9x = ln(x) 9x d dx (xV) - d dx = = d dx (9x In(x)) (as in Solution 1)