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Discuss financial ratios for the purpose of financial analysis: ?mention uses and limitations ?choose three ratios from different categories (such as liquidity, asset management, debt

Discuss financial ratios for the purpose of financial analysis:

?mention uses and limitations

?choose three ratios from different categories (such as liquidity, asset management, debt management, profitability, etc.

image text in transcribedimage text in transcribed
Quellon 11 According to figure B, If the Association of University Economics Professors imposes a price floor of $15, then because of this policy there Not yet priswered will be Formyour of 1100 F Ragquestion PRICE (5) 40.080 60,009 70.060 QUANTITY/TIME Select one: O o. an efficient allocation of economics professors. O b. a surplus of 40 economics professors @ ca shortage of 40 economics professors O d. a shortage of 30 economics professors Previous page Next Page1. Write the dual for each of the following primal problems: Maximize u = -5x1 + 2x2 Minimize z = 6x1 + 3x2 Subject to: Subject to: -xitx2 s -2 6x1 - 3x2 + X3 2 2 2x1 + 3x2 $5 3x1 + 4x2 + X3 25 X1, X2 2 0 X1,X2,X3 20 Maximize u = -x1 + 2x2 - 3x3 Subject to: X1 - X2 5 -2 2x1 + X2 - X3 2 15 Xz + X3 = 10 X1, X2 2 0 X3 unrestricted 2. Find the optimal value of the objective function for the following problem by inspecting only its dual. Do not solve the dual by the simplex method. Explain how you found the answer. Minimize z = 10x1 + 4x2 + 5X3 Subject to: 5x1 - 7x2 + 3x3 2 50 X1,X2, X3 20 3. Consider the following set of inequalities. Note that X1 = X2 = 0 is not a feasible solution. A feasible solution can be found by using the trivial objective function (maximize z = x1 + X2) with the constraints and then solving the dual, from which a solution for the set of inequalities can be found. Find a feasible point with this method (show your work). 2x1 + 3x2 $ 12 -3x1 + 2x2 5-4 3x1 - 5x2 $ 2 x1 unrestricted; x2 2 0 . Consider the following LP. Use the dual problem to show that the basic solution with (x1, *2) = (0,0) is not optimal. Explain why. Maximize z = 2x1 + 4x2 + 4x3 - 3x4 Subject to: X1 + X2 + X3 = 4 X1 + 4x2 + X4 = 8 X1, X2, X3, X4 2 0

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