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distribution with standard deviation of 0.11 ug/m3. From the 75 US urban areas that are randomly sampled, the mean is found to be 7.51 ug/m3
distribution with standard deviation of 0.11 ug/m3. From the 75 US urban areas that are randomly sampled, the mean is found to be 7.51 ug/m3 (for this same PM2.5 concentration). Conduct a hypothesis test at 5% level of significance. (Source: World Health Organization. Concentrations of fine particulate matter (PM2.5). Retrieved from https://www.who.int/data/gho/data/indicators/indicator- details/GHO/concentrations-of-fine-particulate-matter-(pm2-5)) Based on your calculations, what is your statistical decision and conclusion in the context of the problem? Since the p-value is larger than 0.05, fail to reject Ho. At 5% level of significance, the mean PM2.5 concentration is equal to 7.55 ug/m3. Since the p-value is smaller than 0.05, reject Ho. At 5% level of significance, the mean PM2.5 concentration is less than 7.55 ug/m3. Since the p-value is smaller than 0.05, fail to reject Ho. At 5% level of significance, the mean PM2.5 concentration is equal to 7.55 ug/m3. Since the p-value is smaller than 0.05, reject Ha. At 5% level of significance, the mean PM2.5 concentration is equal to 7.55 ug/m3. Since the p-value is larger than 0.05, reject Ho. At 5% level of significance, the mean PM2.5 concentration is less than 7.55 ug/m3.In relation to the Sustainable Development Goals of the United Nations, one of the critical measures being monitored by the World Health Organization is the annual mean concentrations of fine particulate matter of less than 2.5 microns of diameter (or PM2.5, in ug/m3 units] in urban areas. This is the usual indicator of air pollution. As of 2016, the World Health Organization reported that urban areas in the US have an average of 7.55 ug/m3. You believe that this might have declined in the country due to suspension of economic activities (like transportation operations) during the COVlD-19 pandemic. Let us assume the variable follows a normal distribution with standard deviation of 0.11 ug/m3. From the 75 US urban areas that are randomly sampled, the mean is found to be 7.51 ug/m3 (for this same PM2.5 concentration). Conduct a hypothesis test at 5% level of significance. (Source: World Health Organization. Concentrations of ne particulate matter (PM2.5). Retrieved from https://www. who.int/data/gho/data/indicators/indicator details/GHO/concentrations-of-fine-particula te-matter(pm25)) Based on your calculations, what is your statistical decision and conclusion in the context of the problem? 0 Since the p-value is larger than 0.05, fail to reject Ho. At 5% level of significance, the mean PM2.5 concentration is equal to 7.55 ug/m3. 0 Since the p-value is smaller than 0.05, reject Ho. At 5% level of significance, the mean PM2.5 concentration is less than 7.55 ug/m3. 0 Since the p-value is smaller than 0.05, fail to reject Ho. At 5% level of significance, the mean PM2.5 concentration is equal to 7.55 ug/m3. A 2013 study was conducted to determine the energy requirements in non-obese men and women for the purpose of maintaining their current weight. The overall average total daily energy expenditure was 2,443 kcal/d. Assuming this variable follows a normal distribution with standard deviation of 397 kcal/d, conduct a test of significance to determine if this differs from a more recent study in which 95 randomly selected men and women (who claimed to have maintained their weight and body composition for a year) were measured. The sample mean is found to be 2,342 kcal/d. Use 5% level of significance. (Source: for the CALER/E Study Group, Energy requirements in nonobese men and women: results from CALERIE, The American Journal of Clinical Nutrition, Volume 99, Issue 1, January 2014, Pages 71 78, https://doi.org/10.3945/ajcn.1 13.065631) What are the appropriate null and alternative hypotheses? Owns? OHow? 2,443 us Ha: 9? at 2,443 2,342 us Ha: a? at 2,342 O Ho: 11 g 2.342 vs Ha:,u > 2,342 O Ho: 11 = 2.443 vs Ha: u at 2,443 O Ho: 11 = 2.342 vs Ha: ,u ab 2,342
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