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1. [-/2 Points] DETAILS SCALCET8 15.1.001.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Estimate the volume of the solid that lies below the surface z = xy and above the following rectangle. R = ( X , y ) | 0 s x 5 6 , 8 s y s 12 (a) Use a Riemann sum with m = 3, n = 2, and take the sample point to be the upper right corner of each square. (b) Use the Midpoint Rule to estimate the volume of the solid. Need Help? Read It Master It 76% + OK/S 2. [-/13 Points] DETAILS SCALCET8 15.1.001.MI.SA. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Estimate the volume of the solid that lies below the surface z = xy and above the following rectangle. R = ( x , y ) 1 9 5 x = 15 , 5 sys 9) Exercise (a) Use a Riemann sum with m = 3, n = 2, and take the sample point to be the upper right corner of each square. Step 1 We are requested to use m = 3 and n = 2 over the rectangle R = \\ (x, y) | 9 s x s 15, 5 sys 9. The subrectangles are, therefore, as follows.Use a Riemann sum with m = 3, n = 2, and take the sample point to be the upper right corner of each square. Click here to beg Use the Midpoint Rule to estimate the volume of the solid. Recall that in part (a), we saw that the subrectangles are as follows, with AA : 4. Y 9 7 X (9: 5) 11 13 15 Using the Midpoint Rule, the sample points are in the center of each square. For example, when i = 1 and j: l, we are referring to the square in the lower left corner of the grid, with center at (x, y) : ( ) lnl @441 Exercise (a) Use a Riemann sum with m = 3, n = 2, and take the sample point to be the upper right corner of each square. Step 1 We are requested to use m = 3 and n = 2 over the rectangle R = (x, y) | 9 s x s 15, 5 sys 9. The subrectangles are, therefore, as follows. 9 75% + OK/S 7 (9, 5) X 11 13 15 We can estimate the volume of the given solid using the Riemann sum _ _ fxi y; )AA, with i = 1j = 1 f ( x , y ) = xy. Since 9