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Problem:

At a given time, the geocentric equatorial position vector in km of a GPS satellite is

r = 2200I+ 5900J 4000K km Determine the range and elevation relative to a sea-level observer whose latitude is = 40 and longitude = 125. The oblateness parameter of the earth is f = 0.003353. Solutions to ONLY check your work: range: 1988 km, elevation: 26.0 The actual work process needs to be shown for a thumbs up.

6. At a given time, the geocentric equatorial position vector in km of a GPS satellite is r = (2200 + 5900 4000 ) km (6) Determine the range and elevation relative to a sea-level observer whose latitude is o = -40 and longitude 0 = 125. The oblateness parameter of the earth is f = 0.003353. 6. At a given time, the geocentric equatorial position vector in km of a GPS satellite is r = (2200 + 5900 4000 ) km (6) Determine the range and elevation relative to a sea-level observer whose latitude is o = -40 and longitude 0 = 125. The oblateness parameter of the earth is f = 0.003353

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