Do you think we have convincing Number of evidence complaints due 0.294 to suggest to identity Value of p E = P-value that 0.0204 theit (out of Florida is 500) exceeding the national trend? Why? No because a sample proportion 0.296 - 0.294 of 0.296 is 148 0.296 2 = 0.0204 0.461 not that unlikely 2 = 0.098 given the national trend of 0.294. No, because a sample proportion of 0.30 is 150 0.3 z = 0.20 0.3859 not that unlikely given the national trend of 0.294. Yes. because this sample proportion 170 E = s unlikely given the national trend of 0.294. Yes because this sample proportion S VERY 180 z = unlikely given the national trend of 0.294. Yes, because this sample proportion is VERY 190 2 = unlikely given the national trend of 0.294.Looking ahead In the scenario discussed in Question 'I. suppose that a commission in Florida is asked to investigate the types of claims made to the FTC. If Florida follows the national trend. we determined that in a sample of 500 claims; observing 147 {or 29.4%} clue to identitytheft would not be unusual; Would 143 {29.6%} be unusual? How about 150 (30%}? Or I'm [34%]? At what point would you start to think that there is convincing evidence that Florida is exceeding the national trend? Use the data analysis tool at mogggmgthpgthwgghinygppgigiwgrmglpigy ll'to complete the following table and identify a sample proportion which you think is unusual and provides convincing evidence that Florida is exceeding the national trend. Note that in this exercise. if Florida is exceeding the national trend. then we have an upper-tailed test