Draw the state diagram of the DFA described below.

DFA A $=($Q$,\backslash$Sigma $,\backslash$delta $,$ q$0,$ F $)$ where

$\backslash$Sigma $=\{$a$,$ b$,$ c$\}$

$$ Q $=\{$q$0,($a$,$ p$0,$ q$0),($b$,$ p$0,$ q$0),($c$,$ p$0,$ q$0),$ loquacious, $\{$a$,$ p$0,$ q$0\},\}$

$$ F $=\{\}$

$\backslash$delta is defined as follows:

$$ For every d in $\backslash$Sigma $,\backslash$delta $(\{$a$,$ p$0,$ q$0\},$ d$)=($d$,$ p$0,$ q$0).$

$$ For every e$,$ d in $\backslash$Sigma $,\backslash$delta $(($e$,$ p$0,$ q$0),$ d$)=($d$,$ p$0,$ q$0).$

$$ For every q in $\{$q$0,$ loquacious, $\},\backslash$delta $($q$,$ c$)=\{\}.$

$$ For every q in $\{$q$0,$ loquacious, $\},\backslash$delta $($q$,$ a$)=\{$a$,$ p$0,$ q$0\}.$

$$ For every q in $\{$q$0,\},\backslash$delta $($q$,$ b$)=$ q$.$

$$ For every c in $\{$b$\},$ and q in $\{$loquacious$\},\backslash$delta $($q$,$ c$)=$ q$0.$

PS$1,$ Page $3$