During a trip to the beach (Patm=1atm=101.3kPa), a car runs out of gasoline, and it becomes necessary to siphon gas out of the car of a Good Samaritan (Fig. 4). The siphon is a small-diameter hose, and to start the siphon it is necessary to insert one siphon end in the full gas tank, fill the hose with gasoline via suction, and then place the other end in a gas can below the level of the gas tank. The difference in pressure between point 1 (at the free surface of the gasoline in the tank) and point 2 (at the outlet of the tube) causes the liquid to flow from the higher to the lower elevation. Point 2 is located 0.75 m below point 1 in this case, and point 3 is located 2m above point 1 . The siphon diameter is 5mm, and frictional losses in the siphon are to be disregarded. Determine (a) the minimum time to withdraw 4L of gasoline from the tank to the can and (b) the pressure at point 3. [Given the density of gasoline is 750kg/m3.]