dWe need to carry out the following integration for a design dproject and would like to use

${\displaystyle \underset{0}{\overset{4}{}}}xln(x+1)dx$

$($a$)8$ equal internals and your VBA module from ChE $3111$ that was developed for Simpson's $1/3$

rule.

$($b$)9$ equal internals and Simpson's $\frac{3}{8}$ rule. You are encouraged to develop your own Excel

spreadsheet based on what was posted on Canvas or the VBA module from ChE $3111.$

You can print out your Excel$/$VBA spreadsheet results directly as your solutions but please provide

sufficient notes, handwritten or typed, to indicate the Simpson's rule, number of intervals, upper and

lower bounds, and the results of the integration.

The following liquid phase reaction takes place in a CSTR whose volume is $V.$

$AB,-r_A=k{C}_A$

The feed to the reactor has $v_0=5d\frac{m^3}{m}in$ and $C_{A0}=2mo\frac{l}{d}{m}^3.$ Running the reactor at $325K$ and

$350K$ results in conversion $x=0\mathrm{.}7$ and $0\mathrm{.}75,$ respectively. Determine the ratio of $\frac{k(350K)}{k(325K)}.$

Textbook P$1-6.$

$-6_B$ The reaction

$AB$

is to be carried out isothermally in a continuous$-$flow reactor. The entering volumetric flow rate $v_0$ is $10d\frac{m^3}{h}.$ Note: $F_A=C_A.$ For a

constant volumetric flow rate $v=v_0,$ then $F_A=C_A{v}_0.$ Also, $C_{A0}=\frac{F_{A0}}{v_0}=(\frac{15\frac{\text{m}\text{o}\text{l}}{h}}{10d\frac{m^3}{h}})=0\mathrm{.}5mo\frac{l}{d}{m}^3.$

Calculate both the CSTR and PFR volumes necessary to consume $99\%$ of A $($i$.$e$.,C_A=0\mathrm{.}01C_{A0})$ when the entering molar flow rate is $5$

$mo\frac{l}{h},$ assuming the reaction rate $-r_A$ is

a$.-r_A=k$ with Ans.: $\{$:$V_{CSTR}=99d{m}^3]$

b$.-r_A=k_{CA}$ with $0\mathrm{.}0001s^{-1}$

c$.-r_A=k{C}_A^2$ with Ans.: $\{$:$V_{CSTR}=660d{m}^3]$

d$.$ Repeat $($a$),($b$),$ and$/$or $($c$)$ to calculate the time necessary to consume $99\mathrm{.}9\%$ of species $A$ in a $1000d{m}^3$ constant$-$volume ba

reactor with $C_{A0}=0\mathrm{.}5mo\frac{l}{d}{m}^3.$