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Dynamic models - Stirred tank heating process ( Constant holdup ) Assumptions: Perfect mixing Liquid holdup is constant ) = ( w p and C

Dynamic models - Stirred tank heating process (Constant holdup)
Assumptions:
Perfect mixing
Liquid holdup is constant )=(w
p and C are constant
Heat losses are negligible
NF=4-1
=3.
Energy balance:
dUintdt=VCdTdt,=>NfWhichcomindvalesand=3
-(what(H))=w[C(Ti-Tret)]-w[C(T-Tref)]
Parameter: V,,C
Which com take amb, Pariables: T,T,w,w,Q
Nv=4,NE=1;Nf=Nv-NE=4-1=3
eutput: Y, Disturbance:
Manipulated: Q(m).
detail out how we arrive the mass and energy balance equation given in the figure
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