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Dynamic Programming question #2 2. Suppose you're managing a consulting team of expert computer hackers, and each week you have to choose a job for
Dynamic Programming question #2
2. Suppose you're managing a consulting team of expert computer hackers, and each week you have to choose a job for them to undertake. Now, as you can well imagine, the set of possible jobs is divided into those that are low-stress (e.g., setting up a Web site for a class at the local elementary school) and those that are high-stress (e.g., protecting the nation's most valuable secrets, or helping a desperate group of Cornell students finish a project that has something to do with compilers). The basic question, each week, is whether to take on a low-stress job or a high-stress job If you select a low-stress job for your team in week i, then you get a revenue of &, > 0 dollars; if you select a high-stress job, you get a revenue of h > 0 dollars. The catch, however, is that in order for the team to take on a high-stress job in week i, it's required that they do no job (of either type) in week i - 1; they need a full week of prep time to get ready for the crushing stress level. On the other hand, it's okay for them to take a low- stress job in week i even if they have done a job (of either type) in week So, given a sequence of n weeks, a plan is specified by a choice of low-stress," "high-stress," or "none" for each of the n weeks, with the property that if "high-stress" is chosen for week i > 1, then "none" has to be chosen for week i - 1. (It's okay to choose a high-stress job in week 1.) The value of the plan is determined in the natural way: for each i, you add e; to the value if you choose "low-stress" in week i, and you add h, to the value if you choose "high-stress, in week (You add 0 if you choose 31 "none" in week i.)Step by Step Solution
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