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e 3010 Determine the cumulative distribution function for f (x) = 3000 , where x is the time to failure of an electronic component in
e 3010 Determine the cumulative distribution function for f (x) = 3000 , where x is the time to failure of an electronic component in a copier in hours (x > 0). Use the cumulative distribution function to determine the probability that a component lasts more than 5000 hours before failure. Round your answer to three decimal places (e.g. 98.765) P = 0.811 eTextbook and Media Save for Later Attempts: 2 of 3 used Submit AnswerSuppose the cumulative distribution function of the random variable X is 0, x - 1.5) = c) P(X - 0.5) = f) Determine x such that P(x 3) (a) (b) (c) (d) (e) Statistical Tables and Charts Save for Later Attempts: 0 of 3 used Submit AnswerThe probability of a successful optical alignment in the assembly of an optical data storage product is p = 0.8. Assume the trials are independent. Round your answers to four decimal places (e.g. 98.7654). (a) What is the probability that the 1st successful alignment requires exactly 4 trials? (b) What is the probability that the 1st successful alignment requires at most 4 trials? (c) What is the probability that the 1st successful alignment requires at least 4 trials? (a) (b) (c) Statistical Tables and Charts Save for Later Attempts: 0 of 3 used Submit AnswerThe number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a mean of 0.026 failures per hour. {a} What is the probability that the instrument does not fail in an 8hour shift? {bl What is the probability of at least 1 failure in a 24-hour day? Rocnd your answers to tour decimal places {e.g. 98.7654). {a} "he probability is {bl "he probability is Statistical Tables and Charts Save for Later Attempts: U of 3 used
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