e Course:MATH x I e Untitlednctet x I e MicmsoltWoi x I 9 Math 101 cm x I 6 NEwTalJ x II (7)cskvslucki x I D (17)WhatsApr x I I; aregenratedr x u CourseHerc x + c i coursehero.com/qa/wait/39493687l?question_id:39493687 Bangbang124rn Answered 8 hours ago 1.a,b,d,e,f,gandh 2.a,b,candd 4.a,b,c,d,f,gandh 6.aandb Explanation: 1. Aristotle asked, "what is the ultimate purpose of human existence?". He thought that a worthwhile goal should be to pursue "that which is always desirable in itself and never for the sake of something else" (Pursuit of Happiness, 2018). However, Aristotle disagreed with the Cyrenaic view that the only intrinsic good is pleasure (Waterman, 1993). In developing his theory of 'happiness', Aristotle drew upon his knowledge about nature. He contended that what separates man from animal is rational capacity , arguing that a human's unique function is to reason. He went on to say that pleasure alone cannot result in happiness because animals are driven by the pursuit of pleasure and according to Aristotle man has greater capacities than animals (Pursuit of Happiness, 2018). Instead, he put fonNard the term 'eudaimonia'. To explain simply, eudaimonia is defined as 'activity expressing virtue' or what Aristotle conceived as happiness. Aristotle's theory of happiness was as follows: 'fhe function of man is to live a certain kind of life, and this activity implies a rational principle, and the funcfion of a good man is the good and noble performance of these, and if any action is well performed it is performed in accord with the appropriate excellence: if this is the case, then happiness turns out to be an activity of the soul in accordance with virtue' (Aristotle, 2004). A key component of Aristotle's theory of happiness is the factor of virtue. He contended that in aiming for happiness, the most important factor is to have 'complete virtue' or , in other words , good moral character (Pursuit of Happiness, 2008). Aristotle identified friendship as being one of the most important virtues in achieving the goal of eudaimonia (Pursuit of Happiness, 2008). In fact, he valued friendship very highly, and described a 'virtuous' friendship as the most enjoyable, combining both pleasure and virtue. Is this answer helpful? Your feedback will help us match you with the best tutor (5) BAS (Official Video) | JAZ 41 X Course: STAT 100-101 (Winter 20. X WeBWork : STAT-100-101 : Assign X + V X > C a urwork2.edbian.org/webwork2/STAT-100-101/Assignment8/2/?user=200455851&key=hkrzrqacTdi1rJRiitTREB6s4DGMKGHk&effectiveUser=200455851 A Homework Sets Assignment8 Assignment8: Problem 2 Problem 2 User Settings Previous Problem Problem List Next Problem Grades (3 points) Problems We wish to compare the average speed of cars on Albert Street between morning traffic and evening traffic. To do so, a random sample of 15 cars is selected in the morning, and another random sample of 15 cars is selected in the evening. Their speeds are measured. For the morning sample, the mean speed on Albert Street was 56.1 km/h with standard deviation 3.9 km/h. Problem 1 Problem In the evening, the mean was 55.8 km/h with standard deviation 4.0 km/h. Problem 3 Estimate the difference in population means by constructing the 80% confidence interval. Show your relevant steps below. Problem 4 Problem 5 Intermediate Calculations: Problem 6 t value = (Enter the number.) Problem 7 Standard Error = (km/h) Problem 8 Maximum Error of Estimate = (km/h) Final Answer: The 80% Confidence Interval of the difference in mean speeds is (Lower Limit, Upper Limit) = ( km/h km/h) Notes: 1) Use Morning Cars as population #1, and Evening Cars as population #2, and estimate the mean difference (pop#1 minus pop#2, in that order) 2) Keep at least five significant figures for all intermediate values and your final confidence interval. Do not round your confidence interval. 3) This question will attempt to give you partial marks for later parts if they follow correctly from earlier calculations. For example, you may find that your z-value and standard error are marked incorrect, but the maximum error is marked correct. This may be because it follows correctly from the earlier (incorrect) values. To receive full marks on a subsequent attempt, you will need to correctly re-calculate all values. Note: You can earn partial credit on this problem.(5) BAS (Official Video) | JAZ 41 X Course: STAT 100-101 (Winter 20. X WeBWork : STAT-100-101 : Assign X + V X C a urwork2.edbian.org/webwork2/STAT-100-101/Assignment8/3/?key=hkrzrqacTdi1rJRiitTREB64DGMKGHk&user=200455851&effectiveUser=200455851 A Problems We wish to investigate if there is a significant difference between the weights of cherry tomatoes when grown with two different fertilizers. A sample of 260 tomatoes is grown using Fertilizer A. Their mean weight is 13.8 with standard deviation 4.3. Another sample of 170 tomatoes is grown using Fertilizer B. Their mean weight is 13.2 with standard deviation 5.1. Problem 1 Problem 2 Test whether there is a difference in the true mean weights of these tomatoes at a 10% level of significance. Show your relevant steps below. Problem 3 Note: Use "Fertilizer A" as population 1, and "Fertilizer B" as population 2. Problem 4 Problem 5 Step 1: Hypotheses: Problem 6 Problem 7 . The null hypothesis Ho is (choose one): Problem 8 Oul = /2 Oul = 13.8 Oul -/2 = 0.6 Opl = 13.2 For the alternative hypothesis Ha we change the equal sign in Ho to (choose one): 0 Step 2: Rejection Region: The rejection region is bounded by the following critical values: Critical z value(s) =. (Enter critical values from lowest to highest. Leave second blank empty if there is only one critical value.) Step 3: Test Statistic: Standard Error = Calculated test statistic, z = (Keep at least five significant figures for all calculated intermediate values.) Step 4: Decision on HO: At a level of significance of 10% (choose one): O Reject Ho and accept Ha O Fail to reject Ho(5) VIAH : Jassie Gill (Official |41 X Course: STAT 100-101 (Winter 20. X WeBWork : STAT-100-101 : Assign X + V X F -> C a urwork2.edbian.org/webwork2/STAT-100-101/Assignment8/4/?key=hkrzrqacTdi1rJRiitTREB6s4DGMKGHk&user=200455851&effectiveUser=200455851 A A school administrator suspects that the North American version is easier, that is, mean scores on the North American test are higher than those of the International Problem 1 version. Problem 2 To investigate, a random sample of 66 International exams is selected. The sample has mean 61.9 and standard deviation 3.1. A random sample of 119 North Problem 3 American exams has mean 62.7 and standard deviation 7.6. Problem 4 At a 10% level of significance, does the sample evidence support the claim that the North American exam scores are higher? Show your relevant steps below. Problem 5 Problem 6 Note: Use "International" for population 1, and "North American" for population 2. Problem 7 Problem 8 Step 1: Hypotheses: The null hypothesis Ho is (choose one): Oul = 61.9 Opl = /2 Oul - 42 = -0.8 Oul = 62.7 . For the alternative hypothesis Ha we change the equal sign in Ho to (choose one): O Step 2: Rejection Region: The rejection region is bounded by the following critical values: Critical z value(s) =[. (Enter critical values from lowest to highest. Leave second blank empty if there is only one critical value.) Step 3: Test Statistic: Standard Error = Calculated test statistic, z = (Keep at least five significant figures for all calculated intermediate values.) Step 4: Decision on HO: At a level of significance of 10% (choose one): O Reject Ho and accept Ha O Fail to reject Ho