by perpendicular of curvature (iii) A singly protonated ion having M/Z = 375.9 is initially accelerated an electric potential of 5,000 V. After it is accelerated, it enters a homogeneous magnetic field with a strength of 4 T, applied to the path of the ion's travel. Calculate the resultant radius for this ion in the magnetic field {IV=1 JC,1J=1 Kgm's 2,1C=IAS,e=1.602 10- C 1u=1 amu=1.6605 10-27 kg, 1T=1 KgC S=1Kg A's, v velocity=ms }