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earcher wants to study the average lifetime of a certain brand of rechargeable batteries which has been advertised to be 950 hours. She suspects that

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earcher wants to study the average lifetime of a certain brand of rechargeable batteries which has been advertised to be 950 hours. She suspects that the manufactu erstating the battery's capacity. So she select a random sample of 64 batteries from a normal population whose standard deviation she expects to be 200 hours. The ple mean was 920 hours Match the following questions with the corresponding answers. Assume the level of significance to be 0.04. A. Reject the Null B. 3.4% The cut-off number of hours is C. 902.65 The p-value is D. 74.2% Based on her study, the researcher will E. 25.8% Supposed the true mean of the batteries is only 880 hours. What is the F. Not reject the Null Hypothesis. probability of Type ll error? G. 906.25 Suppose the manufacutrer is really cheating the consumers. In reality, the batteries will last only 890 ours. What is the probability that the manufacturer H. 14.7% will be caught? 1. 11.5% J. 7.63%

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