Ed and Taylor work together on a group quiz that has 18 multiple-choice questions, each with 4 choices for the possible answer. Unfortunately, neither had time to study, so they decide to randomly guess at all answers. Ed guesses answers for the rst 7 questions, and Taylor guesses for the other 11 questions. (a) For any single question on the quiz, what is p = chance of a correct guess? p = H (b) Let X = number of correct guesses that Ed makes. What are the values of n and p for the binomial distribution that describes X? (c) Let Y = number of correct guesses that Taylor makes. What are the values of n and p for the binomial distribution that describes Y? (d) Consider X + Y = total correct guesses that Ed and Taylor make. What are the values of n and p for the binomial distribution that deseribes X + Y? n: UH p: Need Help? l [-18 Points] DETAILS PODSTAT4 7.E.044. IY NOTES | ASK YOUR TEACHER PRACTICE ANOTHER Suppose that in a certain metropolitan area, six out of 10 households have cable TV. Let x denote the number among six randomly selected households that have cable TV, so X is a binomial random variable with n = 6 and p = 0.6. {Round your answers to four decimal places.) (a) Calculate p(3) = P(x = 3). M3) = :1 Interpret this probability. 0 This is the probability that exactly 3 out of 10 selected households have cable TV. 0 This is the probability that at least 3 out of 6 selected households have cable TV. 0 This is the probability that exactly 3 Out of 6 selected h0useholds have cable TV. 0 This is the probability that at least 3 out of 10 selected households have cable TV. (b) Calculate p[6), the probability that all six selected households have cable TV. p... = :1 (c) Determine P(x 5 5}. NEWS