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EK 1 3 0 . 6 h : S . ( ) = 1 . 0 mMol / L F ( ) = 1 .

EK130.6 h : S.()=1.0 mMol/L F ()=1.0 m^2/h=7x104 Mol/L Vmax =0.2 mMol(L.h)=

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