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Energy E is an eigenvalue of the Hamiltonian 2. (4 points) Energy E is an eigenvalue of the Hamiltonian H = p2 2m + V,
Energy E is an eigenvalue of the Hamiltonian
2. (4 points) Energy E is an eigenvalue of the Hamiltonian H = p2 2m + V, Hu = Ey . and y is an eigenfunction. Show that energy eigenvalues must be always greater than the minimum of the potential : E > minStep by Step Solution
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