Engineering Economics: Geometric Gradient Cash Flows

What is wrong with my solution below?

There is a discrepancy in the value when computing each single cash flow to EOY- 0 which is seen below:

3. Determine the present equivalent (at time zero) of the following geometric sequence of cash flows. Let i=15.5% jer year and f=10%. Strictly using geometric gradient. P=(A3[ig1(1+i1+g)N])(1+i)2=((1,000)[0.1550.11(1.1551.1)22])(1.155)2 3. Determine the present equivalent (at time zero) of the following geometric sequence of cash flows. Let i=15.5% jer year and f=10%. Strictly using geometric gradient. P=(A3[ig1(1+i1+g)N])(1+i)2=((1,000)[0.1550.11(1.1551.1)22])(1.155)2