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ES At t = 0, the instantaneous position of two pulses moving along a taut string with a speed v = 2.25 cm/s are as
ES At t = 0, the instantaneous position of two pulses moving along a taut string with a speed v = 2.25 cm/s are as shown in the diagram below. Each unit on the horizontal axis is 2.0 cm and each unit on the vertical axis is 2.0 cm. y pulse 1 - - - - - X C - - - - - - pulse 2 (a) At what location will the resultant of the two pulses have minimum amplitude? cm (b) At what time will the resultant of the two pulses have minimum amplitude? S (c) What is the value of this minimum amplitude? cmDate Page So/ Pulse - 1 # V= 2.25 (m / s , 4 cm resultantant pulse ( mininumw) amplitude) 2 Cm 22 24 28 8 20 T B 2 CI 2 4 6 8 10 12 14 16 com) Koizycam y em * = 14 CM Pulse - 2 ") The location when the resultant of the two pulses have minimum amplitude, of Since, the amplitude of resultant wave havemininum value, that is, the path difference to between them is zeroo y "c ) The value of minimum amplitude , a = Q - as = BCm - 6 cm = +2 cm where a : the amplitude of pulse - 1 an = the amplitude of pulse - 2
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