Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Estimate the diffusion coefficient of a mixture of air and water vapor at 17, 21, 44 and 59C. A)Using the Chapman-Enskog theory and the Fuller,

Estimate the diffusion coefficient of a mixture of air and water vapor at 17, 21, 44 and 59C.

A)Using the Chapman-Enskog theory and the Fuller, Schettler and Giddings method.

B) Using the experimental value of Table 9.1-1 at 25 C and Eq.(9.1-5)

image text in transcribed

image text in transcribed

Equation 9.1-5: (DAB)T2,P2=(DAB)T1,P1(P2P1)(T1T2)3/2DT2DT1 Tabla 9.1-1 Experimental values of the diffusion coefficient for Binary gas mixtures at 1atm1 \begin{tabular}{|l|c|c|} \hline \multicolumn{1}{|c|}{ Mezcla binaria } & Temperatura (K) & Coeficiente de difusin (cm2/s) \\ \hline Aire & & \\ Acetato de etilo & 273 & 0.071 \\ Agua & 289 & 0.282 \\ & 298 & 0.260 \\ & 13 & 0.277 \\ & 333 & 0.305 \\ Amoniaco & 273 & 0.198 \\ Benceno & 298 & 0.096 \\ Bromo & 293 & 0.091 \\ Cloro & 273 & 0.124 \\ Dixido de azufre & 273 & 0.122 \\ Dixido de carbono & 273 & 0.136 \\ Disulfuro de carbono & 273 & 0.088 \\ Etanol & 298 & 0.132 \\ Eter etilico & 293 & 0.0896 \\ Helio & 276 & 0.624 \\ Hidrgeno & 273 & 0.611 \\ Metanol & 298 & 0.162 \\ Mercurio & 614 & 0.473 \\ Naftaleno & 298 & 0.061 \\ Nitrobenceno & 298 & 0.087 \\ n-Octano & 298 & 0.060 \\ Oxigeno & 273 & 0.176 \\ Tolueno & 298 & 0.084 \\ Yodo & 298 & 0.083 \\ Argn & & \\ Nen & 293 & 0.329 \end{tabular} Equation 9.1-5: (DAB)T2,P2=(DAB)T1,P1(P2P1)(T1T2)3/2DT2DT1 Tabla 9.1-1 Experimental values of the diffusion coefficient for Binary gas mixtures at 1atm1 \begin{tabular}{|l|c|c|} \hline \multicolumn{1}{|c|}{ Mezcla binaria } & Temperatura (K) & Coeficiente de difusin (cm2/s) \\ \hline Aire & & \\ Acetato de etilo & 273 & 0.071 \\ Agua & 289 & 0.282 \\ & 298 & 0.260 \\ & 13 & 0.277 \\ & 333 & 0.305 \\ Amoniaco & 273 & 0.198 \\ Benceno & 298 & 0.096 \\ Bromo & 293 & 0.091 \\ Cloro & 273 & 0.124 \\ Dixido de azufre & 273 & 0.122 \\ Dixido de carbono & 273 & 0.136 \\ Disulfuro de carbono & 273 & 0.088 \\ Etanol & 298 & 0.132 \\ Eter etilico & 293 & 0.0896 \\ Helio & 276 & 0.624 \\ Hidrgeno & 273 & 0.611 \\ Metanol & 298 & 0.162 \\ Mercurio & 614 & 0.473 \\ Naftaleno & 298 & 0.061 \\ Nitrobenceno & 298 & 0.087 \\ n-Octano & 298 & 0.060 \\ Oxigeno & 273 & 0.176 \\ Tolueno & 298 & 0.084 \\ Yodo & 298 & 0.083 \\ Argn & & \\ Nen & 293 & 0.329 \end{tabular}

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Fundamentals Of Momentum Heat And Mass Transfer

Authors: James Welty, Gregory L. Rorrer, David G. Foster

7th Edition

111972354X, 978-1119723547

More Books

Students also viewed these Chemical Engineering questions

Question

Networking is a two-way street. Discuss this statement.

Answered: 1 week ago