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et L Sigma ? be a regular language. Then there is an NFA M = ( Q , Sigma , delta ,

et L \Sigma ? be a regular language. Then there is an NFA M =(Q,\Sigma ,\delta , q0, F ) that
recognizes the language L. But we want an NFA for the language L. So we build an
NFA M =(Q,\Sigma ,\delta , q0, Q \ F ). This does not seem to work in general. To show this,
(a) Give an example of an NFA M for which L(M ) L(M').
(b) Give an example of an NFA M for which L(M )= L(M').
(c) Give an example of an NFA M for which L(M ) L(M').

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