Ethanol vapor is being absorbed from a mixture of alcohol vapor and water vapor by means of a non$-$volatile solvent in which alcohol is soluble but water is not. The temperature is $97$degC and PT $=760$ mmHg$.$ The alcohol vapor can be considered to be diffusing through a film of alcohol$$water vapor $0\mathrm{.}1$ mm thick. The mole percent of the alcohol in the vapor at the outside film is $80\%$ and that on the inside, next to the solvent is $10\%.$ The volumetric diffusivity of alcohol$$water vapor mixtures at $25$degC and $1$ atm is $0\mathrm{.}15$ cm$^2/$s$.$ Calculate the rate of diffusion of ethanol vapor in kg$/$hr if A $=10$ m$^2.$