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Ethyl ethanoate (CH3CO2C2H5) can be formed by the reaction of ethene (C2H4) with ethanoic acid (CH3COOH) in an inert solvent according to the reaction below.

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Ethyl ethanoate (CH3CO2C2H5) can be formed by the reaction of ethene (C2H4) with ethanoic acid (CH3COOH) in an inert solvent according to the reaction below. C2H4+CH3COOHCH3CO2C2H5 0.075 moles of ethene are allowed to react with 0.052 moles of ethanoic acid, the total volume being made up to 200mL. When equilibrium had been established the mixture was found to contain 0.045 moles of ethyl ethanoate. Calculate the value of Kc under these conditions

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