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Evaluate the definite integral ( int_{0}^{2} (4x - x^2) dx ) and interpret the result as the area between the curve ( y = 4x

  • Evaluate the definite integral ( \int_{0}^{2} (4x - x^2) dx ) and interpret the result as the area between the curve ( y = 4x - x^2 ) and the ( x )-axis over the interval ([0, 2]).

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