Evaluate the function f(x) at the given numbers (correct to six decimal places). f ( x ) = - X2 - 8x , x = 8.5, 8.1, 8.05, 8.01, 8.005, 8.001, 7.9, 7.95, 7.99, 7.995, 7.999 x2 - x - 56 f(8.5) = f (8.1 ) = f(8.05) = f(8.01) = f(8.005) = f(8.001) = f ( 7.9 ) = f(7.95) = f(7.99) = f(7.995) = f(7.999) = Guess the value of the limit of f(x) as x approaches 8, correct to six decimal places. (If an answer does not exist, enter DNE.) lim X2 - 8X X-8 X2 - X - 56Evaluate the function f(x) at the given numbers (correct to six decimal places). f ( x ) = - X2 - 4x x = 0, -0.5, -0.9, -0.95, -0.99, -0.999, -2, -1.5, -1.1, -1.01, -1.001 x2 - 3x - 4 f(0 ) f(-0.5) = f(-0.9) = f(-0.95) = f(-0.99) = f(-0.999) = f ( - 2 ) f(-1.5) = f(-1.1) = f(-1.01) = f(-1.001) = Guess the value of the limit of f(x) as x approaches -1, correct to six decimal places. (If an answer does not exist, enter DNE.) x2 - 4x lim X-> -1 x- - 3x - 4Tutorial Exercise Find the limit, if it exists. lim 3x + 30 x- -10 |x + 10| Part 1 of 5 Recall that |x + 101 = 3 x + 10 x 2 -10 -(x+ 10) x -10- [x + 10| x - -10Use the Squeeze Theorem to show that lim (x2 cos 11xx) = 0. Illustrate by graphing the functions f(x) = -x2, g(x) = x2 cos 1lax, and h(x) = x on the same screen. Let f(x) = -x2, g(x) = x2 cos 11xx, and h(x) = x2. Then -1 @