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Evaluate the function h (x) =x2+2x for the given value of x. Simplify your answer. Determine the x- and y-intercepts for the given function. Write

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Evaluate the function h (x) =x2+2x for the given value of x. Simplify your answer. Determine the x- and y-intercepts for the given function. Write your answer as an ordered p s (x) = - x+3 If there is more than one answer, separate your answers with commas. Select "None" if app Part 1 of 2 x-intercept(s) : (0,0) 0,0,... None X 5Determine the x- and y-intercepts for the given function. Write your answer as an ordered pair. s(x)=-|x|+3 If there is more than one answer, separate your answers with commas. Select "None" if appropriate. y-intercept(s): E] Determine the domain and range of the function. 3- 2 - 1- - 2 2 -1- -2- - 3- Part 1 of 2 The domain of the function is 0 0,0,... X 5 Part 2 of 2 The range of the function is 0,0,... X 5Determine the domain and range of the function. 3 - 2- 1 - x A -3 - 2 -1 -1- - 3- Part 1 of 2 The domain of the function in interval notation is (0,0) [0,0) (0,0] [0,0] OO - OO X 5 Part 2 of 2 The range of the function in interval notation is (0,0) [0,0) (0,0] [0,0] 00 - OO XDetermine the domain and range of the function. Ty 4+ 2- 1- x - 3 -2 -1 2 3 -2- -3- Part 1 of 2 The domain of the function in interval notation is [0,0] (0,0] [0,0) (0,0) OO - OO X Part 2 of 2 The range of the function in interval notation is [0,0] (0,0] [0,0) (0,0) - OO X 5Write the domain in interval notation. (a) k (x ) = x+4 X - 3 (b) j (x) = x+4 x 2+ 3 (c) p(x) = *+4 x 2 - 3 Part 1 of 3 (a) k (x) = - x + 4 x - 3 The domain in interval notation is DVD [0,0] [0,0) (0,0] (0,0) OO -0o OVO X 5 Part 2 of 3 (b) j (x) =* x+4 x 2 + 3 The domain in interval notation is DVD [0,0] [0,0) (0,0] (0,0) OO -00 OVO X Part 3 of 3 (c) p(x) = x+4 2 - 3 The domain in interval notation is. DVD [0,0] [0,0) (0,0] (0,0) OO -00 OVO X 5Write the domain in interval notation. (a) a (x) =Vx+36 (b) b (xx)=36-x (c) c (x) = Vx+ 36 Part 1 of 3 (a) a (x)= x+36 The domain in interval notation is DVD [0,0] [0,0) (0,0] (0,0) -OC X Part 2 of 3 (b) b (x) =36-x The domain in interval notation is. DVD [0,0] [0,0) (0,0] (0,0) 00 - OO X Part 3 of 3 (c) c (x) = 1 Vx + 36 The domain in interval notation is Ovo [0,0] [0,0) (0,0] (0,0) 0O -OO XWrite the domain in interval notation. (a) w (x)= x +4+10 (b) y (xx) = x x + 4+ 10 X (c) z (x) =- x + 4 - 10 Part 1 of 3 (a) w (x)= x + 4+ 10 The domain in interval notation is DVD [0,0] [0,0) (0,0] (0,0) OO -OO X 5 Part 2 of 3 (b) y (x) = T x x + 4 + 10 The domain in interval notation is. [0,0] [0,0) (0,0] (0,0) OO - OO X Part 3 of 3 ( c) z (x) = x x + 4 - 10 The domain in interval notation is Ovo [0,0] [0,0) (0,] (0,0) 00 -OOUse the graph of y= f (x) to answer the following. 10 4 -3 -2 2 -2- -30 0 4- Part 1 of 8 (a) Determine f (-3). f ( - 3 ) =] X Part 2 of 8 (b) Determine f (3). f (3 ) = X Part 3 of 8 (c) Find all x for which f (x) = -1. If there is more than one value, separate them with commas or write your answer in interval notation, if necessary. Select "None", if applicable. Value(s) of x for which f (x) = -1: [0,0] (0,0] [0,0) (0,0) 0.0... OO None X Part 4 of 8 (d) Find all x for which f (x) = -3. If there is more than one value, separate them with commas or write your answer in interval notation, if necessary. Select "None", if applicable

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