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Evaluate the given integral by changing to polar coordinates. ff sin(x2 + 1(2) cm, where R is the region in the first quadrant between the
Evaluate the given integral by changing to polar coordinates. ff sin(x2 + 1(2) cm, where R is the region in the first quadrant between the circles with center the origin and radii 3 and 4 R [cos[16) cos[9)) i\\J|-=I
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