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Evaluate the indefinite integral as a power series. 1 dx 6+ 9x2 E (-1)~n*((3~(n+1))/2~(n)+ +C n=0 Subm Answ 3 +1 2n+1 (-1)2 /99 Previous Tries
Evaluate the indefinite integral as a power series. 1 dx 6+ 9x2 E (-1)~n*((3~(n+1))/2~(n)+ +C n=0 Subm Answ 3 +1 2n+1 (-1)2 /99 Previous Tries on+1 2n +1 This discussionEvaluate the indefinite integral as a power series. 1 dx 6+ 9x2 E (-1)~n*((3~(n+1))/2~(n)+ +C n=0 Subm Answ 3 +1 2n+1 (-1)2 /99 Previous Tries on+1 2n +1 This discussionEvaluate the indefinite integral as a power series. 1 dx 6+ 912 (-1)~n*((3~(n-1))/2~(n+ +C n=0 Subm e a2n+1 at answer before Incorrect. Tries 6/99 Previous Tries (-1)" on+1 2n +1 This discussionf ( 1 ) ( a ) A Maclaurin series is given by f (a) = k k! k=0again both the Answer one equal. so our last Answers was also correct We have verified it with basic method for different in value Thus 37 -1 6 + 9 2 2 = C 250 27+d 22 + 1let's verily ous parlous series. We had f ( W ) = when mao = 6 m = 1 1 x ( - 15# [ 2] x2 : X = 2 y . MF 2 X * 24 & So series terms one 12 2 + 3 2 4 6 8 hence both are equal. -Now take the integration of it E DC - 23 + 3265 6 72 Now verify if we our last final Answer. = S( -1)n 3h-1 . 2 27+1 27+2 When m = 0 (- 1) * 3-1 X 6 m= 1 2 - 1x X x3 = 2 = 1 x 12 Pw / W X 3 x5 4vS let's try other way to verily our Answer let's find out power sunleg ? gh 46 $ 8 ( 0 ) = 6 - 22 ( 32 + 2) 2 8" ( 20 ) 5 2192 2 - 2 ) =2 5"10 ) 5 - 1 (3 xx 2 +2 )3 8" ( 21 ) = 72 x ( 2- 3x2) 3 5(0)- 0 ( 3 2 2 +9 )4 S ( 2 ) = 72 ( 24 x 2 ( 32 2 - 2)#- ( 2- 5 x2)( 32 2+2) ) (32 2+ 2)5 " (0 ) = let's put in power searles formuly, x6 + + 9 22 4 1! 2 1 1 3 2 4 So 6+ 92 2 6 - 16 2 2 + 3 x4
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