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Evaluate the integral of sec^5 (x) tan*3 (x) dx * 1/3 sec^3 (x) + 1/5 sec^5 (x) + C 1/7 sec*7 (x) - 1/5 sec
Evaluate the integral of sec^5 (x) tan*3 (x) dx * 1/3 sec^3 (x) + 1/5 sec^5 (x) + C 1/7 sec*7 (x) - 1/5 sec 5 (x) + C 1/3 tan*3 (x) + 1/5 tan^5 (x) + C 1/7 tan*7 (x) - 1/5 tan^5 (x) + C Evaluate the integral of: * dx x2 - 2x + 50 O arcsec (x - 1)/7+ C 1/7 arctan (x - 1)/7 + C O 7 arcsin (x - 1)/7 + C O 1/7 arcsec (x - 1)/7 + C O arcsin (x - 1)/7 + C O 7 arcsec (x - 1)/7 + C O arctan (x - 1) + C O 7 arctan (x - 1)/7 + CSuppose we wish to find the integral of x dx/(1+x^4), the first step to solve this is by Using U-substitution O Substitute "tan(a)" to "x" O Substitute "sin(a)" to "x" Using inverse trigonometric formula In the integration What is the value of u? a. N - Alex b. = C. N - lux d. N = her O A O B O c O D
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