Question: Evaluate the surface integral I=(xdy dz + xy dz dx + xz dxdy). where S is the surface bounded by z = 0, z

Evaluate the surface integral I=(xdy dz + xy dz dx + xz dxdy). where S is the surface bounded by z = 0, z =

Evaluate the surface integral I=(xdy dz + xy dz dx + xz dxdy). where S is the surface bounded by z = 0, z = b, x + y = a. OR By transformation to a triple Integral, evaluate I = f(xdy dz + xy dzdx+xzdxdy), where S is the surface bounded by z = 0, z = b, x + y = a.

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