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Evening Morning No, remembered less than 60% of 19 28 the items Yes, remembered at least 60% of 11 26 the items Evening Morning No,

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Evening Morning No, remembered less than 60% of 19 28 the items Yes, remembered at least 60% of 11 26 the items Evening Morning No, remembered less than 60% of 0.6333333 0.5185185 the items Yes, remembered at least 60% of 0.3666667 0.4814815 the items 2. (2 points) Based on the proportions In #1, does It appear that the proportion remembering at least 60% of the Items Is different between those who performed the activity In the morning and those who performed the activity In the evening? Briefly explain. 3. (3 points) State the null and alternative hypotheses In statistical notation. Define the notation In the context of the problem.> chisq . test (tb], correct = FALSE) Pearson's chi-squared test data : tbl X-squared = 1.0316, df = 1, p-value = 0. 3098 > X2 X2$expected Late Early No 16. 78571 30. 21429 Yes 13. 21429 23. 78571 > X2$expected 4. (2 points) Report the expected counts for all cells In the table. Are the expected counts "large enough" for conclusions from the chi-square test to be valld to the population? Briefly explain. 5. (2 points) Report the chi-square statistic with degrees of freedom and the p-value here. 6. (4 points) Answer the question of Interest In the context of the problem.2-sample test for equality of proportions without continuity correction data: table (memorygameStime, memorygame$pctremember) X-squared = 1.0316, df = 1, p-value = 0. 3098 alternative hypothesis: two. sided 95 percent confidence interval: -0. 1031207 0. 3327503 sample estimates : prop 1 prop 2 0. 6333333 0. 5185185 7. (5 points) Report and Interpret the 95% confidence Interval for the difference In the population proportion remembering at least 60% of the Items between those who did the activity In the morning (labeled "early" In the data set) and those who did the activity In the evening (labeled "late" In the data set): (Pearly - Plate)

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