Answered step by step
Verified Expert Solution
Question
1 Approved Answer
everything is included for all questions and the images are clearly visible. A person walks into a room that has, on opposite walls, two plane
everything is included for all questions and the images are clearly visible.
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 5.00 ft from the mirror on the left wall and 10.0 ft from the mirror on the right wall. first image ft second image ft third image ftAt an intersection of hospital hallways, a convex mirror is mounted high on a wall to help people avoid collisions. The mirror has a radius of curvature of 0.600 m. Locate the image of a patient 10.8 m from the mirror. E m Localion of the image V Determine the magnification of the image. E x Describe the image. (Select all that apply.) C] enlarged C] upright U inverted Cl virtual C1 real C] diminished At an interseu' E J "Location afthe image- Determine (h in from of the mirror E behind the mirror Describe the C] enlarged -x mirror is mounted high on a wall to help people avoid collisions The mirror has a radius of curvature of 0.600 ml Locate the image of a patient 10.8 m from the mirror. C] upright C] inverted C] virtual C] real C] diminished A concave spherical mirror has a radius of curvature of 12.0 cm. Locate the image for each of the following object distances (Enter 0 for M and the distance if no image is formed.) (a) an = 24.0 cm in from of the mirror, real, and upright in from of the mirror, real, and inverted M : E ' E c behind the mirror, virtual, and upright behind the mirror, virtual, and inverted no image is formed A concave makeup mirror is designed so that a person 29 cm in front of it sees an upright image magnified by a factor of two. What is the radius of curvature of the mirror? R=Em a A contact lens is made of plastic with an index of refraction of 1.34. The lens has an outer radius of curvature of +2.04 cm and an inner radius of curvature of +2.58 cm. What is the focal length of the lens? :cm A converging lens has a focal length of 20.0 cm. Locate the images for each of the following object distances. (Enter 'infinity' for the image distance if necessary.) For each case, state whether the image is real or virtual and upright or inverted. Find the magnification. (If there is no answer for a blank enter N/A. ) (a) 40.0 cm cm --location of the image-- V O no image formed O real, upright O real, inverted O virtual, upright O virtual, inverted magnification (b) 20.0 cm cm --location of the image-- V O no image formed O virtual, inverted O real, inverted O virtual, upright O real, upright magnification c) 10.0 cm cm --location of the image-- V O inverted, real O inverted, virtual O erect, real O erect, virtual O no image formed magnificationA converging lens has a focal length of 20.0 cm. Locate the images for each of the following object distances. (Enter 'infinity' for the image distance if necessary.) For each case, state whether the image is real or virtual and upright or inverted. Find the magnification. (If there is no answer for a blank enter N/A. ) (a) 40.0 cm V --location of the image-- O no image in front of the lens O real, upr beyond the lens O real, inv no image formed O virtual, upright O virtual, inverted magnification (b) 20.0 cm cm --location of the image-- V O no image formed O virtual, inverted O real, inverted O virtual, upright O real, upright magnification c) 10.0 cm cm --location of the image-- V O inverted, real O inverted, virtual O erect, real O erect, virtual O no image formed magnification7. [-11 Points] SERESSEN1 23.P.0294 A diverging lens has a focal length of -24.0 cm. Locate the images for each of the following object distancest For each case, state whether the image is real or virtual and upright or inverted, and find the magnification. (a) 48.0 cm Em 0 real, erec 0 real, inverted 0 virtual, erect 0 virtual, inverted magnification :x (b) 24.0 cm S cm --Localion ofimageu v 0 real, erect 0 real, inverted 0 virtual, erect O virtuall inverted magnification :x (c) 12.0 cm S cm -Localion ofimageu v 0 real, erect 0 real, inverted 0 virtual, erect 0 virtual, inverted magnification :X 7. [11 Points] SERESSEN1 23.P.0294 A diverging lens has a focal length of -24.0 cm. Locate the images for each of the following object distances. For each case, state whether the image is real or virtual and upright or inverted, and find the magnification. (a) 48.0 cm E c J "Location a! image 0 real: are' in front of the lens 0 real, inv- behind the lens 0 virtual, e no image formed 0 virtual, inverted magnification :x (b) 24.0 cm S cm -Localion of image-- v 0 real, erect 0 real, inverted 0 virtual, erect 0 virtual, inverted magnification :x (c) 12.0 cm S cm -Localion of image- V 0 real, erect 0 real, inverted 0 virtual, erect 0 virtual, inverted magnification :x 8. [-/1 Points] DETAILS SERESSEN1 23.P.036. An object is placed 18 cm to the left of a converging lens of focal length 29 cm. A diverging lens of focal length 12 cm is 25 cm to the right of the converging lens. Find the position and magnification of the final image. cm9. [-/1 Points] DETAILS SERESSEN1 23.P.040. Two converging lenses having focal lengths of 14.0 cm and 20.0 cm are placed 50 cm apart, as shown in Figure P23.4. The final image is to be located between the lenses, at the position indicated. IS Object Final image 31.0 cm - 50.0 cm Figure P23.44 (a) How far to the left of the first lens should the object be positioned? cm (b) What is the overall magnification of the question? x(c) Is the final image upright or inverted? O upright O inverted10. [-/1 Points] DETAILS SERESSEN1 23.P.045. The lens and mirror in Figure P23.51 are separated by 1.00 m and have focal lengths of +80.8 cm and -49.2 cm, respectively. If an object is placed 1.00 m to the left of the lens, locate the final image. Object Lens Mirror -1.00 m - 1.00 m Figure P23.51 93 = cm ---Location--- State whether the image is upright or inverted, and determine the overall magnification. The image is ---Location--- V , and the overall magnification is M = XStep by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started