E-W WIND LOAD PARTA = 1.000 LBS WEWNO LOAD PART 1000 LBS Consider the utility pole with guy-wire/cables as shown. The utility pole supports power-lines from both sides with sag as shown. The angle of the power-line sag-tangent-line with horizontal from both sides is 22 degrees, and the weight of power-lines at the end (at the pole) is 500 lbs as shown. POWER LINE WEIGHT 500 LBS POWER LINE WEIGHT 500 LBS a) Find the forces in the guy-wire/cables and the utility pole, with vertical and horizontal reactions, due to the weight of power-lines and with wind force of 1,000 lbs East to West. b) Find the forces in the guy-wire/cables and the utility pole, with vertical and horizontal reactions, due to the weight of power-lines and with wind force of 1,000 lbs West to East. HINT. Note that Utility-Pole & the Guy-wire/Cables are two force members, and can only take axial force. In the addition, cables can only resist tension, and they become inactive if the force is compression Therefore depending on the direction of the wind, only one of the cables will be active TENSION CABLE GUY WARD UTILITY POLE TENSION CABLE GUY WIRE) Show all your work with force diagram and explain each step of your work. Write the equations of equilibrium that apply and solve to prove summation of forces are zero CABLE ANCHORAGE CABLE ANCHORAGE ONCRETE MASS TO CONTERACT CABLE TENSION CONCRETE MASS TO CONTERACT CABLE TENSION