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Example 3.3: Given the values of the two principal specific heats, S, = 3400 cal kg! K-' and S, = 2400 cal kg- K-' for

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Example 3.3: Given the values of the two principal specific heats, S, = 3400 cal kg"! K-' and S, = 2400 cal kg- K-' for the hydrogen gas, find the value of J if the universal gas constant R = 8300 J kg- K-1.Example 3.4: The difference between the two molar specific heats of a gas is 8000 J kg"' K-'. If the ratio of the two specific heats is 1.65, calculate the two molar specific heats

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