Example

differential equation

Given: - 7 3 x dy = 70cy + 520 8 2 4 = 3x ( 52 2 /3 ) From 2) 4 = 32 ( 52c 43 ) = 15 (x( 3 ) (20 2/3 ) {: (a ) ( an ) = amt 9+ 2 3+3 = 15 OC => 15 0C 11/3 4 = 1520 differentiate y with respect to 4' = 15. d ( x ) = 15 / 14 ) 20 3 - 1 x 8 /3 y = 55 ( 20 ) differentiate again with respect to ac y" = d [ 55 ( 20 ) 8/3 7 dac .. d ( I'm ) = A (x ) 8/3 = 55 2 ( x ) 8/3 - 1 = 55 w / 0 ( 2C ) 4 = 440 5/3 3 NOW , put this value of y" into given equation