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exceed critical value 1.64.) 3. Using the data in he above exercise, (a) Construct a 95% confidence interval for p. .5375 # 1.96*SE with SE

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exceed critical value 1.64.) 3. Using the data in he above exercise, (a) Construct a 95% confidence interval for p. .5375 # 1.96*SE with SE 7 0.02493 gives interval [.489,.586) (b) Construct a 9% confidence interval for p. .5375 + 2.58*SE with SE = 0.02493 gives interval [.473,.602]c) Withoutany additionalcalculations testthe hypothesisHO:p=.5, H1:p#.5 atthe5% ignificance level. Not rejected since .5 belongs in al's interval

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