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Exercise #2- Control Range Conversions Convert the following to find the missing factors (in yellow) in the items below. Use the formula below and
Exercise #2- Control Range Conversions Convert the following to find the missing factors (in yellow) in the items below. Use the formula below and show your math. Value a - LRV A x spanB +LRV B Span A Value b = Where LRV=Lower Range Value URV = Upper Range Value = Span URVA - LRVA or URV B - LRV B Example 0-50 PSIG 4-20 mA 25 PSIG 12 mA SIG|4-20 mA|25 i Calculations for the above example Span A (Process Range) Span B (Output Signal) Value b= 50-0-50 20-4 16 Value LRV x Span, +LRV Value b= 25-0 x 16+4 B Span 50 Value b 12mA Process Range Output Signal Current Process Reading (Value) 200-800 F 4-20 mA 3. 4 + 0-1000 GPM 4-20 mA 250 GPM Current Signal Reading (Value) F14 mA 100-300 PSI 3-15 PSI PSI 6 PSI 5. 6. Explain how a transmitter is calibrated. mA
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