1. Exercise Gear. A company sells exercise clothing and equipment on the Internet. To design clothing, data on physical characteristics of different types of customers is collected. The weight, in kilograms, of 24 female randomly selected runners are recorded:

62.8

56.9

58

48.1

57.3

54.7

50.4

53.9

55.9

64.2

58.7

63.3

59.7

60.6

51

52.8

61

57.9

48.6

60

50.8

55.4

64.3

56.7

1. Give the 95% confidence interval for the mean weight of the population of all female runners.

x= 56.7917 s =4.8078 and n = 24

at 95% confidence level and n-1=23 degrees of freedom t =2.069

CI = 56.7917 + 2.069*4.8078/24

(54.7615 , 58.8218)

1. Based on this confidence interval, does a test of

H0: =56.3

Ha: 56.3

reject H0 at the 5% significance level? Explain.

from the sample given ,mean=56.79 stdev =4.81 n=24

t=(x-u)/(stdev/sqrt(n))=(56.79-56.3)/(4.81/sqrt(24))=0.4991

t test stat value is 0.4991

p value =T.DIST.2T(t test stat,df)=T.DIST.2T(0.4991,23)

=0.622

p value =0.622

at a =0.05 p value > 0.05

Do not reject because there is not enough evidence to conclude that the mean weight of female runners differ from 56.3

1. Give the t statistic and its p-value for this test.
2. I was wondering if you could help me with his question. Above is the answers to question one and two i need help with question Give the t statistic and its p-value for this test.