Exercise II Sulphur presents two lines: Ka,= 5.37216 and Kaz=5.37496 1. What is the energy difference expressed in eV, between Ka, and Kaz 2. If it is known that the width at the mid-height of these lines is 5 eV, what conclusion can be drawn 3. If the position of the Ka, line increases by 0.002 when passing from S6+ to S, show that this has no impact upon the location of this photoelectron in energy terms